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The distance to the moon can be computed as follows.

We know that:

* acceleration due to gravity at the Earth's surface is about EQN:9.8ms^{-2}.

** this can be measured using a pendulum in your living rioom

** this can be measured using a pendulum in your living room

* the orbital period of the moon relative to the stars is about 27.3 days.

* acceleration due to gravity decreases as the inverse square.

* the radius of the Earth is 6366km.

** Measured by Eratosthenes

OK, so acceleration in a circle is EQN:v^2/r or EQN:\omega^2r where /r/ is the

radius of the orbit, and EQN:\omega is the rotational velocity. That's

27.3 days divided by EQN:2\pi giving 1/375402 radians/second. Hence acceleration

in the orbit is EQN:(1/375402)^2r where /r/ is the (unknown) distance from

the centre of the Earth to the Moon.

But acceleration due to gravity is EQN:9.8(r/R)^{-2} where /R/ is the radius of the

Earth, so equating these we get:

* EQN:(1/375402)^2r=9.8(R/r)^2

so

* EQN:r^3=9.8(R^2)(375402)^2

This gives an answer of 382517km, which is amazingly close to the figure

quoted on WikiPedia of an average centre-centre distance of 384,403km.

Accurate to 0.1%.

Finally, Orbital Velocity is given by EQN:v=\omega{r} , and that now works

out as 382517/375402 km/s, or almost exactly 1.02km/s.

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Part of the Farrago of Fragments.